IITJEE: Electric Field (E), Potential (V) Graphs & Capacitor Dielectrics

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Apex Class • IITJEE Electrodynamics Lab

Electric Field (E), Potential (V) Graphs & Capacitor Dielectrics Lab

Compare Hollow vs. Solid Sphere E & V Graphs and master Dielectric Insertion (Battery Connected vs. Disconnected)!

🌐 Select a Charge Distribution to Inspect E(r) and V(r) simultaneously:
E(r) Electric Field r = R (Surface) r → E_in = 0! E_max = kQ / R² E_out ∝ 1/r² V(r) Electric Potential r = R (Surface) V_in = kQ/R (Const!) V_out = kQ / r (∝ 1/r) 🎯 #1 JEE Trap: Inside a Hollow/Conducting Sphere, E = 0 because V = Constant (since E = -dV/dr = 0), NOT because V = 0! E(r) Solid Dielectric Sphere r = R E_in ∝ r E_out ∝ 1/r² V(r) Solid Sphere (V_center = 1.5 V_s!) r = R V_c = ³⁄₂ (kQ/R) V_s = kQ/R 🔮 Solid Sphere Formula: V_in = [kQ / (2R³)] (3R² – r²) → At Center (r = 0), V_center = 1.5 × V_surface! E_x (Axial Electric Field of Ring) +x (Along Axis) → ★ E_max at x = +R / √2 x = +0.707 R x = -R / √2 ⭕ Ring Formula: E_axis = kQx / (R² + x²)³/² | At Center (x=0): E = 0, V_max = kQ/R | At x = ±R/√2: dE/dx = 0 (Maxima)! -q +q Dipole p = q(2a) → E_axial = +2kp / r³ → (Parallel to p, V_axial = kp/r²) ← E_eq = -kp / r³ (Anti-parallel to p!) Equatorial Potential V_eq = 0 Everywhere! ➕➖ Dipole Scaling Law: For a short dipole, E ∝ 1/r³ and V ∝ 1/r² | Magnitude Ratio: |E_axial| = 2 |E_equatorial|!
Internal Field (r < R)
E_in = 0 (Zero!) E_in = kQr / R³ (∝ r) At Center (x=0): E = 0 E_axial = 2kp / r³
Gauss’s Law Application
Internal Potential (r < R)
V_in = kQ / R (Const!) V_center = 1.5 (kQ/R) V_x = kQ / √(R² + x²) V_axial = kp/r² | V_eq = 0
E = -dV / dr Relation
Maximum Field Value
kQ / R² (At Surface) kQ / R² (At Surface) 2kQ / (3√3 R²) |E_axial| = 2 |E_eq|
Peak Location Check
Self-Energy / Torque
U = kQ² / (2R) U = (3/5) kQ² / R Small osc: ω = √(kQq/mR³) τ = p × E | U = -p · E
High-Yield JEE Formula
🔋 Insert Dielectric Slab (K = 3) into Parallel Plate Capacitor. Select Circuit State:
+Q₀ (+ + + + + + + +) -Q₀ (- – – – – – – -) Air Gap (K = 1): E₀ = σ / ε₀ = V₀ / d Baseline Air Capacitor Values • Capacitance: C₀ = ε₀ A / d • Stored Energy: U₀ = ½ C₀V₀² = Q₀² / (2C₀) • Force Between Plates: F = Q₀² / (2Aε₀) • Energy Density: u = ½ ε₀ E₀² (J/m³) 💡 Force between capacitor plates F = Q²/(2Aε₀) is independent of separation distance d! 🔌 BATTERY DISCONNECTED (Isolated Plates → Charge Q = Q₀ Locked!) Dielectric Slab (K = 3) Polarization reduces E to E₀ / K! Induced Charge: Q_ind = Q₀ (1 – 1/K) Effect of Dielectric (Battery Disconnected) ✅ Charge (Q): Q = Q₀ (CONSTANT!) 📈 Capacitance (C): C = K C₀ (Increases K×) 📉 Voltage & Field: V = V₀/K | E = E₀/K 📉 Energy U = Q₀²/(2KC₀) = U₀ / K (Drops!) 🧲 Why Energy Drops (U₀ → U₀/K): The capacitor pulls the dielectric slab in, doing positive mechanical work! ⚡ BATTERY CONNECTED (Voltage V = V₀ & Field E = V₀/d Locked!) V₀ Dielectric Slab (K = 3) Battery pumps extra charge ΔQ = (K-1)Q₀! Total Charge Q = K Q₀ = 3 Q₀! Effect of Dielectric (Battery Connected) ✅ Voltage & Field: V = V₀ | E = E₀ (CONSTANT!) 📈 Capacitance (C): C = K C₀ (Increases K×) 📈 Charge (Q): Q = K Q₀ (Increases K×) 📈 Energy U = ½(KC₀)V₀² = K U₀ (Increases K×!) ⚡ JEE Comparison: U_connected / U_disconnected = (K U₀) / (U₀ / K) = K² (For K = 3, Ratio is 9 : 1)! Slab Thickness t (Dielectric K) Air Gap (d – t): Field = E₀ Total d t Partial Dielectric & Metal Slab Formulas C = ε₀ A / [ d – t + (t / K) ] • Copper / Metal Slab (K = ∞): C_metal = ε₀ A / (d – t) • Potential Difference: V = E₀(d – t) + (E₀/K)t 🧱 Effective Thickness Trick: A dielectric slab of thickness t behaves like an air gap of reduced thickness (t / K)!
Capacitance (C)
C₀ = ε₀ A / d C = K C₀ (Increases!) C = K C₀ (Increases!) ε₀A / (d – t + t/K)
Always Increases with K
Plate Charge (Q)
Q₀ = C₀ V₀ Q = Q₀ (Constant!) Q = K Q₀ (Increases K×) Q_ind = Q (1 – 1/K)
Conservation of Charge
Voltage (V) & Field (E)
V₀ | E₀ = V₀ / d V₀ / K | E₀ / K (Drops!) V₀ | E₀ (Constant!) E_slab = E₀ / K
V = E × d Relation
Stored Energy (U)
U₀ = ½ C₀ V₀² U = U₀ / K (Decreases!) U = K U₀ (Increases!) U = Q² / (2C)
Use Q²/2C when Q=Const; ½CV² when V=Const
🔥 2 High-Frequency JEE Capacitor Sharing Formulas (Connecting C₁ at V₁ & C₂ at V₂):
1. Common Potential: V_common = (C₁V₁ + C₂V₂) / (C₁ + C₂)  (Use minus sign if opposite plates are connected: C₁V₁ – C₂V₂).
2. Heat Loss During Charge Sharing: ΔU_loss = ½ [C₁C₂ / (C₁ + C₂)] (V₁ – V₂)² — notice it has the exact same form as Inelastic Collision KE loss!

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